T=-16t^2+100

Solution for T=-16t^2+100 equation:

=-16T^2+100

We move all terms to the left:

-(-16T^2+100)=0

We get rid of parentheses

16T^2-100=0

a = 16; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·16·(-100)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$T_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*16}=\frac{-80}{32}
=-2+1/2
$
$T_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*16}=\frac{80}{32}
=2+1/2
$